Question

a ball generally dropped in height of 20 m. if its velocity increase uniformly at the rate 10 m/s^2,With what velocity will it strike the ground .after time will it strike the ground

Answer 1

V =( 2gh)^1/2
= (2 × 10 × 20)^1/2
=✓400
= 20m/s
T =✓2h/g
=✓2 × 20/10
=√4
=2 seconds
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Answer 2

S=20meters
U=0m/s
A=10m/s^2

3rd law of motion,
V^2=u^2+2as
V^2=0^2+2(10)(20)
V^2=0+400
V=20m/s

1st law of motion,
V=u+at
20=o+10(t)
t=20/10
t=2seconds