Question

A ball having a certain mass is moving with a velocity v0 on a horizontal surface. The ball collide with a stationary ball having four times its mass. The first ball immediately comes to rest after collision then with what velocity will the second ball move.

Answer 1

Given
Velocity of the first ball = v0
Mass of the first ball = m
Mass of the second ball = 4m

To find
Velocity of the second ball = ?

Formula used :-
1) Momentum (P) = Mass (m) * Velocity (v)

Solution

According to the law of conservation of momentum

v0 * m = 4m * Velocity of the second ball after collision
Therefore,
Velocity of the second ball after collision = m*v0/4m = v0/4 = 1/4*v0 = 0.25 v0

Hope this helps you !

Answer 2

Answer:

Explanation:

yes the correct answer is 0.24 and this comes when 1/4=0.25 (its a hint) try yourself , will surely come to sucess

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