Question

A ball having the potential energy of
1000 J is dropped from a height of 100
m. At approximate what height (in
metres) will the kinetic energy be 5 times
the potential energy at that height?
16.6
a.
36.3
b.
66.6
C.
d. 83.3​

Answer 1

PE = M*G*H

1000=M*G*100(As given in question)

M*G=1000/100

M*G=10-----> Eq. 1

K+P=1000

5P+P=1000 (K=5P)

6P=1000

6*M*G*H=1000(PE=MGH)

6*M*G*H=1000

6*10*H=1000

H=1000/60

H=16.6