Question

A ball hits a wall horizontally at 6.0 m/s. It rebounds horizontally at 4.4 m/s. The ball is in contact with the wall for 0.04 s. What is the acceleration of the ball?

Answer 1

u = -6 m/s ( initial )
v = 4.4 m/s ( final ) 
t = 0.04 s 
a=?
  = v-u/t
  = 4.4-(-6)/0.04
  = 10.4/0.04 
  = 260 m/s² ( answer )
 

Answer 2

GIVEN ;-

⇒ Speed of Ball at which it hits the ball in horizontal way = 6.0 m / s

⇒ Speed of ball when the ball rebounds in horizontal       = 4.4. m / s

⇒ Time take by the ball for contact to wall is                  = 0.04 s

TO FIND  ;-

⇒ Acceleration of the ball = ?

SOL  ;-

Initial velocity of the ball = 6.0 m / s

Final velocity of the ball  = - 4.4. m / s

Time taken by the ball     = 0.04 s

Acceleration =  Final velocity - Initial velocity / Time taken

                   =  - 4.4 m / s      -         6. 0 m /s   /  0.04 s

                   =   10.4 m/ s         /       0.04 s
       
                   = 260 m / s² is the acceleration of the ball.