Question

a ball hits a wall horizontally at 6.0m/s. it rebounds horizontally at 4.0m/s. the ball is in contact with the wall for 0.040s.what is the acceleration of the ball.

Answer 1

Initial velocity = 6 m/s ( forward )

Final velocity = 4.4 m/s ( backward ) = -4.4 m/s ( forward )

Acceleration = change in velocity / time

= ( -4.4 - 6 ) / 0.04 = -10.4/0.04

= -1040/4 = -260 m/s² ( forward )