Question

a ball hits a wall horizontally at 6 m/s . it rebounds horozontally at 4.4m/s . the ball is in contact with the wall for 0.04 sec . what is the accelaration of the ball

Answer 1

Initial velocity(u) =6m/s
Final velocity(v) = -4.4m^s (as it rebounds)
Time (t)=0.04s
Acceleration =(v-u)/t
= (-4.4- 6)/ 0.04
= -10.4/0.04
= -260m^s

So the acceleration of the ball will be -260m/s^2.