Question

A ball hits a wall horizontally at 60
m/s rebounds horizontally at 4.4 m/s. The ball is in contact
the wall for 0.040 s. What is the acceleration of the ball ?
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Answer 1

Answer:

• initial velocity =6.0m/s-¹
• final velocity =4.4m/s-¹(forward direction)

-4.4m/s-¹(backwards direction)

time =0.040 s

here is ur answer buddy:

a=v-u/t

a=-4.4-6/0.04

=-10.4/0.04

=-1040/4

=-260m/s-²

$\mathfrak \red{thnx}$