A ball hits a wall horizontally at 6m/s. it rebounds horizontally at 4.4m/s. the ball is in contact with the wall for 0.04s. what is the acceleration of the ball?
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hello friend..!!
in the question it is given that ,
⇒ u = 6 m/s.
⇒ v = 4.4 m/s .
⇒ t = 0.04 s.
to find the acceleration ,
we know that a = ( v - u) / t
implies, a = ( 4.4 - 6 ) / 0.04
therefore a = - 40 m/s² .
therefore the acceleration of the ball is -40 m/s²
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hope it is useful..!!
in the question it is given that ,
⇒ u = 6 m/s.
⇒ v = 4.4 m/s .
⇒ t = 0.04 s.
to find the acceleration ,
we know that a = ( v - u) / t
implies, a = ( 4.4 - 6 ) / 0.04
therefore a = - 40 m/s² .
therefore the acceleration of the ball is -40 m/s²
----------------------------------------------------------------
hope it is useful..!!
Vivekstar23:
answer is wrong
correct answer is -260 m/s2
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