Question

A ball hits a wall horizontally at 8m/s. It rebounds horizontally at 4 m/s. The ball is in contact with the wall for 0.05 sec. What is the acceleration of the ball?​

Answer 1

Explanation:

initial velocity=8m/s

final velocity=4m/s

time=0.05s

a=v-u/t

a=4-8m/s/0.05s

a= -156m/s square

Answer 2

Given :-

A ball hits a wall horizontally at 8m/s. It rebounds horizontally at 4 m/s. The ball is in contact with the wall for 0.05 sec

To find :-

What is the acceleration of the ball ?​

Formula Used :-

$\huge\sf a = \dfrac{v - u}{t}$

Solution :-

$\sf a = \dfrac{4 - 8m/sec}{0.05}$

a =  -156m/s²

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