a ball hits a wall horizontally with a velocity of 6 m per second after hitting was it rebounds horizontally with a velocity of 4.4 M per second if the ball remains in contact of all for 0.040 second the acceleration would be
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Answer. we have, v=4.4 m/s u=6 m/s t=0.04 s NOW, we know, a=v-u/t a=6-4.4/0.04 a=1.6/0.04 a=160/4 a=40 m/s²
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Her there is a tricky question
let's start
u = 6m/s
v = -4.4m/s ( because if we take one quantity positive then we take one negative)
t = 0.04 sec
so a = v-u/t
A = -10.4/0.04
a = -260m/s^2
please mark me as a brainlist.
I know it is a question of S. Chand class 9
q. no 60 ( probably) it's a good question. it has come in my. exam. please suscribe my channel TOPPERS ACADEMY.
let's start
u = 6m/s
v = -4.4m/s ( because if we take one quantity positive then we take one negative)
t = 0.04 sec
so a = v-u/t
A = -10.4/0.04
a = -260m/s^2
please mark me as a brainlist.
I know it is a question of S. Chand class 9
q. no 60 ( probably) it's a good question. it has come in my. exam. please suscribe my channel TOPPERS ACADEMY.
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