A ball hits a wall horizontaly at 6.0 m/s . it rebounds horizontally at 4.4m/s . the ball is in contact with the wall for 0.040 sec. What is the acceleration of the ball?
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ok so the answer is
a = v-u/t
u = 6m/s
v = 4.4m/s
t = 0.040 s
4.4-6/0.040 = 1.6/0.040
=40m/ssquare
a = v-u/t
u = 6m/s
v = 4.4m/s
t = 0.040 s
4.4-6/0.040 = 1.6/0.040
=40m/ssquare
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