Question

a ball hits a wall with 30m/s and rebounces back with same velocity. what is the change in velocity?

Answer 1

initial velocity(u)=30m/s   final velocity(v)=(-30)m/s (-ve sign becuase the ball's dircn is in opposite of initial velocity)

change in velocity=final velocity-inital veloc.=30-(-30)=60m/s

please hit thanks and rate it :)

Answer 2

Answer:

The correct answer to this question is 60 m/s.

Explanation:

Given - A ball hits a wall with 30m/s and rebounds back with same velocity.

To find - what is the change in velocity?

The magnitude of change in velocity of the ball is 60 m/s.

A ball hits a wall at 30 m/s and bounces back at the same speed. The initial velocity is 30 m/s, and as it rebounds, the direction changes, resulting in a final velocity of (-30 m/s). Final velocity minus beginning velocity equals the change in velocity as follows:

Δ$v = v-u$

Δ$v = (-30) - (30)$

= $-60m/s$

So, the magnitude of change in velocity of the ball is 60 m/s.

#SPJ2