Question

A ball hits a wall with a speed of 30m/s and rebounds with same velocity.What is the change in its velocity?

Answer 1

change in velocity is final-initial velocity.If we assume the initial direction to be +ve then final directiom of ball will be -ve as velocity has direction.So change in velocity will be -30 - 30=-60 or if u assume the signs in opposite way then change is 30-(-30)=60

Answer 2

The magnitude of change in velocity of the ball is 60 m/s.

Explanation:

We have,

A ball hits a wall with a speed of 30 m/s and rebounds with same velocity. We can say that initial velocity is 30 m/s and when it rebounds its direction changes i.e. final velocity is (-30 m/s). The change in velocity is given by final velocity minus initial velocity as :

$\Delta v=v-u\\\\\Delta v=(-30)-(30)\\\\\Delta v=-60\ m/s$

So, the magnitude of change in velocity of the ball is 60 m/s.

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A ball hits a wall with a speed of 30m/s and rebounds with same velocity.What is the change in its velocity?

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