Question

A ball hits horizontally at 6.0ms-1. It rebounds horizontally at 4.4 ms-1. The ball is in contact with the wall for 0.04 s. What is the acceleration of the ball​

Answer 1

$GIVEN :-$

• Initial Velocity = 6m/s
• Final Velocity = -4.4 m/s (Forward) and 4.4 m/s (backward)
• Time Taken = 0.04 seconds

$TO \ FIND :-$

• The Acceleration of the Ball

$SOLUTION :-$

$Accleration = \dfrac{Final\:Velocity - Initial\:Velocity}{time}$

★ Substituting the given values

$\implies\:\:Acceleration = \dfrac{(-4.4 - 6)}{0.04}$

$\implies\:\:Acceleration = \dfrac{-10.4}{0.04}$

$\implies\:\:Acceleration = \dfrac{-1040}{4}$

$\implies \:\:{\boxed{Acceleration = -260m/s^{2}}}$

$\therefore$ Acceleration of the ball is $\red{-260m/s^{2}}$