A ball id dropped from height h on a horizontal floor goes up to the height 3h/4 after hitting the floor fraction of energy of ball lost in the impact is
Answers
Answered by
51
pls mark as brainliest
Attachments:
Answered by
129
Hey dear,
◆ Answer-
∆E/Ei = 0.25
◆ Explaination-
# Given-
h' = 3h/4
# Solution-
Here, we have to consider potential energy of the system.
Initially,
Ei = mgh
Finally-
Ef = mgh'
Ef = 3mgh/4
Fractional loss of energy-
∆E/Ei = (Ei-Ef)/Ei
∆E/Ei = (mgh-3mgh/4)/(mgh)
∆E/Ei = 1/4 = 0.25
Therefore, fraction of energy of ball lost in the impact is 0.25 .
Hope it helps ...
◆ Answer-
∆E/Ei = 0.25
◆ Explaination-
# Given-
h' = 3h/4
# Solution-
Here, we have to consider potential energy of the system.
Initially,
Ei = mgh
Finally-
Ef = mgh'
Ef = 3mgh/4
Fractional loss of energy-
∆E/Ei = (Ei-Ef)/Ei
∆E/Ei = (mgh-3mgh/4)/(mgh)
∆E/Ei = 1/4 = 0.25
Therefore, fraction of energy of ball lost in the impact is 0.25 .
Hope it helps ...
Similar questions