Physics, asked by muskanlark3578, 1 year ago

A ball id dropped from height h on a horizontal floor goes up to the height 3h/4 after hitting the floor fraction of energy of ball lost in the impact is

Answers

Answered by max20
51
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Answered by gadakhsanket
129
Hey dear,

◆ Answer-
∆E/Ei = 0.25

◆ Explaination-
# Given-
h' = 3h/4

# Solution-
Here, we have to consider potential energy of the system.

Initially,
Ei = mgh

Finally-
Ef = mgh'
Ef = 3mgh/4

Fractional loss of energy-
∆E/Ei = (Ei-Ef)/Ei
∆E/Ei = (mgh-3mgh/4)/(mgh)
∆E/Ei = 1/4 = 0.25

Therefore, fraction of energy of ball lost in the impact is 0.25 .

Hope it helps ...
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