Question

A ball iis thrown vertically upward.velocity at 1/3 rd of. Maximum height from ground is 8 m/ s. The velocity withwhich rhe ball was thrown is (take g = 10 m/s) a) 4✓2 b) 4✓3 c) 4✓6 d) 2✓6 m/s

Answer 1

Answer:c-4√3

Explanation:Max height is u^2/2g so one third of it is u^2/6g...now use eqn v^2=u^2+2gs and put s as I told above v is give as 8m/s gis given 10 now you can easily find u