A ball in thrown vertically upward to a hight of 25m. Then calculate the initial velocity by which it was thrown, and the time take by it to rise this height.
Answers
Answered by
1
Answer:
Correct option is
C
30 m/sec.
At the point 25m above it takes 4 sec. i.e., time of flight there is 4 s.
4=
g
2u
u=20m/s
at 25m height it has velocity 20m/s and it goes further height of
2g
u
2
=20m
Total max height =20+25=45m
Initial velocity.
45=
2g
u
2
u=30m/s
Explanation:
Answered by
1
Answer:
u=?,v=0,g=-9.8m/s²,h=25m
v²-u²= 2gh
0-u=-9.8multiply by 25
-u=-49
u=49
s=ut+1/2gt²
s=49+1/2 multiply by (-9.8) into 5²
h=122.5m
Total time = 5+5 = 10s
Explanation:
Wjy I took T= 5s because it is the same sum in my textbook
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Hope it helps out
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