Question

A ball initially most to words East with a speed 10 m/s changes its direction of motion towards north in root 2
the magnitude of average acceleration will be

Answer 1

Answer:

Intial velocity=v1=5m/seast wards

then after time t=10sec

v2=5m/s north wards

δv=

V

1

2

+

V

2

2

=

25

+25

=5

2

acceleration a=

time

velocity

=

10

5

2

=

2

2

×

2

2

=

2

1

towards n-w