Question

A ball initially moving at a speed of 25 m/s is acted upon by a constant retardation of 2.5 m/s2. For how long will the ball roll before coming to rest?​

Answer 1

Answer:

The ball covers a distance of 125m.

Hope my answer is helpful

Answer 2

Answer:

the distance rolled by the ball to reach in rest position = 125 meter

Step by step explanations :

given that,

A ball initially moving at a speed of

25 m/s

here,

initial velocity of the ball = 25 m/s

also given that,

It is acted upon by a constant retardation of 2.5 m/s²

and comes to rest

here,

acceleration of the ball = -2.5 m/s²

let the time taken by the ball to reach in rest position be t

now,

we have,

initial velocity(u) = 25 m/s

final velocity(v) = 0 m/s [ball comes to rest]

acceleration(a) = -2.5 m/s²

time taken = t

by the equation of motion,

v = u + at

putting the values,

0 = 25 + (-2.5)t

-2.5t = -25

t = -25/-2.5

t = 10 s

now,

let the distance rolled by the ball to reach rest be s

by the equation of motion,

S = ut + ½at²

putting the values,

S = 25(10) + ½(-2.5)(10)(10)

S = 250 - 125

S = 125 m

So,

the distance rolled by the ball to reach in rest position

= 125 meter