Question

A ball initially moving towards east with a speed 10 m/s , change its direction of motion towards north ( keeping speed constant ) in root 2 s. the magnitude of avg acceleration......u know answer than answer.....​

Answer 1

Answer:

10√2

Explanation:

avg acceleration = 10+10/√2

= 20/√2×√2/√2

= 10√2

Answer 2

Answer:

Magnitude of average acceleration is 10m/s².

Explanation:

Given is a ball moving with speed of 10m/s towards east and changes its direction to north in $\sqrt{2}$ seconds.

Average acceleration is the change in velocity of the body in a second.

Initial speed of the ball= 10i

Final speed of the ball= 10j

Change in Velocity=  Final speed - Initial speed

$average\ acceleration=\frac{10j-10i}{\sqrt{2} }=\frac{\sqrt{10^{2}+ 10^{2} } }{\sqrt{2} }=\frac{\sqrt{200} }{\sqrt{2} }=10m/s^{2}$

Hence, Magnitude of average acceleration of the ball is 10m/s².