Question

A ball is allowed to fall from the top of a building 51 is time taken to first ball One by fourth of its height and t2 is time taken to fall Last One by fourth of its height t2/t1​

Answer 1

Answer:

Explanation:

Given A ball is allowed to fall from the top of a building t1 is time taken to first ball One by fourth of its height and t2 is time taken to fall Last One by fourth of its height t2/t1

Now according to question we get

H = 1/2 gt^2

So t1 = √h/2 g

Let time t be the remaining height to cover will be 3h/4

So t = √3h/2g

Now let time T to cover total height will be  

So T = √2h/g

So time to cover h/4 distance will be t2

So t2 = T – t

So t2 = √2h/g - √3h/2g

Now t2 / t1 = √2h/g - √3h/2g / √h/2 g

So t2 / t1 = √2g2h - √3hg / √g 2g  x √2g / √ h

= √gh(2 - √3) /√gh

Or t2/t1 = 2 - √3

Answer 2

Answer:

will be the correct answer hope it helps you t2/t1=2-√3