Question

A ball is allowed to fall from the top of the tower of height 10 m calculate the velocity of the ball just before it touches the ground

Answer 1

Explanation:

Initial velocity =0m/s

Acceleration=9.8m/s

Distance =10m

From kinematics equation we have.

v^2-u^2=2as

Where ,. u is the initial velocity

v is the final velocity

s is the distance

a is the acceleration

So,

v^2–0=2*9.8*10

v^2=196

V=√196=14

Hope it helps you..