A ball is allowed to fall from top of a building. If t1,s
time taken to fall first 1/4th of its height and t2, is time
taken to fall last 1/4th of its height then,
t1/t2 is
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Answer:
t1t2 = (h/2g)∧1.5/(T + t )
Explanation:
h/4 = gt1²/2
3h/4 = gt²/2
h = gT²/2
h/4 = (T² - t²)g/2 = (T+t)gt2l2 = gt1²/2
t1² = (T+t)t2
t2 = h/ 2g(T + t )
t1 = √h/2g
t1t2 = (h/2g)∧1.5/(T + t )
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