Question

A ball is allowed to fall from top of a building. If t1,s
time taken to fall first 1/4th of its height and t2, is time
taken to fall last 1/4th of its height then,
t1/t2 is
​

Answer 1

Answer:

t1t2 = (h/2g)∧1.5/(T + t )

Explanation:

h/4 = gt1²/2

3h/4 = gt²/2

h = gT²/2

h/4 = (T² - t²)g/2 = (T+t)gt2l2 = gt1²/2

t1² = (T+t)t2

t2 = h/ 2g(T + t )

t1 = √h/2g

t1t2 = (h/2g)∧1.5/(T + t )