a ball is drop from a height 20 m if the if the mass if ball is 2 kg calclulate the speed and kinetic energy it reaches the ground
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v²-u² = 2gs
where v= final velocity
u= initial velocity
g = gravitational constant = 9.8m/s²
s = distance covered
now u =0
then
v² = 2*9.8*20= 392m²/s²
now kinectic energy is mv²/2
mass m = 2 kg
then kinectic energy
2*392/2=392j
v = √392m/s
where v= final velocity
u= initial velocity
g = gravitational constant = 9.8m/s²
s = distance covered
now u =0
then
v² = 2*9.8*20= 392m²/s²
now kinectic energy is mv²/2
mass m = 2 kg
then kinectic energy
2*392/2=392j
v = √392m/s
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