Question

A ball is drop from rest on a cliff. What is the speed of the ball 5secs later?

Answer 1

PART-I

By using the first equation of motion

v=u+gt

here,

v= 0+9.8*5

v=49m/s

PART-II

Acceleration due to gravity remains constant for the motion we can easily solve the equation by using the second equation of motion is

s=ut+1/2at2

s=ut+1/2at2 s=0+1/2*9.8*25

s=ut+1/2at2 s=0+1/2*9.8*25 s=4.8*25

s=ut+1/2at2 s=0+1/2*9.8*25 s=4.8*25 s=122.5m.

°•✮•°HOPE ITS HELPFUL FOR YOU°•✮•°

°•✮•°Please mark me as BRAINLIST°•✮•°

Answer 2

Hope it helps you...

Please mark me as BRAINLIST....