a ball is droped from a height of 176.4m. how much time will take to reach the ground with formula
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176.4= 9.8t^2/2
18= t^2/2
36= t^2
t= 6sec for the first ball to touch the water surface when released from the 176.4 m height.
2nd ball has to take 4sec to reach the water surface
176.4= u4+9.8*16/2
176.4–78.4= u4
98= 4u
u=24.5.sec.
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