A ball is droped from a high rise platform t = 0 starting from rest. After 6 s another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v ?
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Distance of 1st ball= S= 1/2 x 10 x 18
= 1620
= 1620Distance of 2nd ball = S' = ut + 1/2gt²
1620 = 12u + 5 x 144
u = 135 - 60
= 75 m/s
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