Question

a ball is dropped at the height of 60 meter vafter how much time and with what velocity does the ball reach to the ground? If acceleration is 10m/sec^2 in down ward direction.
in proper explanation​

Answer 1

Answer:

as it is free fall we can apply

t=√2h/√g

√2×60/10

2×√3

=3.4 sec

velocity:√2hg

Answer 2

so,

given: H=60m, a=10m/so

we have to find time and velocity

By 2nd kinematical eq u=0 As Object initially at rest

H=1/2at^2

60=1/2×10×t^2

60=5×t^2

60/5=t^2

2√3=t

so put t in 1st kinematical eq

v=at

v=10×2√3