A ball is dropped at the speed of 0⁄. from a height of 40 metre. If its velocity increases uniformly at the rate of 10/² , with what velocity will it strike the ground? After what time will it strike the
ground?
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20 m/s, 2 s
Given, initial velocity of ball, u=0
Final velocity of ball, v=?
Distance through which the balls falls, s=20m
Acceleration a=10ms
−2
Time of fall, t=?
We know
v
2
−u
2
=2as
or v
2
−0=2×10×20=400 or v=20ms
−1
Now using v=u+at we have
20=0+10×t or t=2s
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