Question

A ball is dropped downwards after 1 second another ball is dropped downwards from the same point what is the distance between them after 3 seconds

Answer 1

Answer:

Distance between the two balls

= 40 meter

Step by step explanations:

given that,

A ball is dropped downwards after 1 second

here,

initial velocity of the ball = 0 m/s

[ball was at rest]

let distance covered by this ball be S१

also given

after 1 second another ball is dropped downwards from the same point

initial velocity of this will also 0

let distance covered by this ball be S२

here,

to find ,

the distance between them after 3 seconds

for S१ time for falling = 4 seconds,

so,

S१ = ut + ½ gt²

here,

u = initial velocity

t = time taken

g = gravitational Acceleration

here we have,

initial velocity(u) = 0 m/s

gravitational acceleration(g) = -10 m/s²

time taken(t) = 4 seconds

so,

S१ = ut + ½gt²

putting the values

S१ = (0)(4) + ½ (-10)(4)(4)

S१ = -80 m

so

distance covered by the first ball = -80 m

now,

for second ball

time taken by falling = 3 seconds

S२ = ut + ½ gt ²

putting the values,

S२ = 0(3) + ½(-10)(3)(3)

S२ = -45 m

so,

distance covered by second ball = -45 m

now,

we have,

S१ = -80 m

S१ = -80 mS२ = -45 m

displacement between them = S१ - S२

= -80 - (-45)

= - 80 + 45

= - 40 m

Negation of displacement shows distance towards the earth

so,

Distance between the two balls

= 40 meter

Answer 2

Answer:

distance between them = 40 meter

Explanation:

Refer to the attachment

sorry for the bad handwriting