Question

A ball is dropped freely from certain height. find its speed after 5 sec​

Answer 1

Step-by-step explanation:

in this case we know u=0 (assumed),a=g=9.81m/s^2, t=5s, and we want to find v, so we use the equation

v=u+at=0+9.81(5)

v=49.05m/s

so, the velocity on impact is 49.05m/s

Answer 2

Answer:

Given :-

• A ball is dropped freely from certain height.

To Find :-

• What is the speed after 5 sec ?

Solution :-

Given :

• Initial Velocity (u) = 0 m/s
• Acceleration due to gravity (g) = 9.8 m/s²
• Time Taken (t) = 5 sec

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{v =\: u + gt}}$

where,

• v = Final Velocity
• u = Initial Velocity
• g = Acceleration due to gravity
• t = Time Taken

So, by putting those values we get,

$\implies \sf v =\: 0 + 9.8(5)$

$\implies \sf v =\: 0 + (9.8 \times 5)$

$\implies \sf v =\: 0 + 49$

$\implies \sf\bold{\underline{v =\: 49\: m/s}}$

$\therefore$ The speed after 5 sec is 49 m/s .