Question

A ball is dropped from 80m height. Distance covered by it in 4th second is..

Answer 1

We know, s = ut + 1/2at^2

or, s = 1/2 × 9.8 × 16

or, s = 78.4 m

HOPE THIS COULD HELP!!!

Answer 2

Answer:

Explanation:

distance travelled by ball in 4th second=distance travelled by ball with 4second-distance travelled by ball in 3rd second

s=ut+1/2 at^2

u=0

s=1/2 at^2

s=(1/2 * 9.8 *4^2) -(1/2*9.8*3^2)

s=78.4-44.1

s=34.3

s=35