Question

A ball is dropped from a 100 m high tower. How much time will it take to reach the ground? What is the velocity of the ball just before hitting the ground? (g=9.8 m/s^2)​

Answer 1

Answer:

v=44.688 m/s

t=4.56 s

Explanation:

u=0

S=h=100 m

a=+g= 9.8 m/s²

S=ut+1/2gt²

100=1/2×9.8×t²

t²=20.83 s

t=4.56 s

v=u+at

  =gt

  =9.8×4.56

   =44.688 m/s

hope it helped and please mark as brainliest:)

Answer 2

Answer:

t=4.5s

v=44.1m/s

HOPE IT HELPS