Question

A ball is dropped from a balloon going up at a speed of 10ms if the ballon was at hieght 40m the maximum height reached by the ball with respect to the balloon??

will mark as the brainliest ans , if i am satisfied by the ans

Answer 1

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HEY!!

✔s = ut + (1/2)at2

✔s = 60 m

✔u = -7 m/s

✔a = 10 m/s^2

✔As per the formula 60 = -7t + 5t^2

✔-5t^2 + 7t = 60

✔By solving the above quadratic equation further, we will get

▶▶t = 4.23 secs

Answer 2

Answer:

Explanation:

Given,

Initial Velocity(u) = 10m/s

Height(h) =  40m

To Find :-

The maximum height reached by the ball with respect to the balloon?(h_max)

Formula required :-

$h_{max}=h+\dfrac{u^2}{2g}$

[ g = 10 m/s^2]

Solution :-

$h_{max}=40+\dfrac{(10)^2}{2\times 10}$

$=40+\dfrac{100}{20}$

 = 40 + 5

= 45m

$h_{max}=45m$

Know More :-

1) v = u + at

2) s = ut + 1/2 at²

3) s = vt - 1/2at²

4) a = v - u/t

5) v²-u² = 2as