A ball is dropped from a balloon going up at a speed of 7 metre per second. if the ball was at a height 60 M at the time of dropping the ball, how long will the Ball taken in reaching the ground?
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Answered by
4
hey dear
here is your answer
initial velocity = 0 (as ball is dropped from some height)
final velocity = 7 m/s
height = 60 meter
time taken = ?
g = 9.8 = 10 m/s²(approx. value of g
so, by the second equation of motion,
s = ut+1/2gt²
60 = 0+1/2*10*t²
t² = 60/5
t² = 12
t = 3.46seconds
hope it helps :)
here is your answer
initial velocity = 0 (as ball is dropped from some height)
final velocity = 7 m/s
height = 60 meter
time taken = ?
g = 9.8 = 10 m/s²(approx. value of g
so, by the second equation of motion,
s = ut+1/2gt²
60 = 0+1/2*10*t²
t² = 60/5
t² = 12
t = 3.46seconds
hope it helps :)
Answered by
1
heya dear your answer is here..
_____$___$$____$$___$__$$
here u=0m/s
v=?
g=10m/s^2
t=?
s=60m
s=ut+(at^2)/2
60=(0*t)+(10t^2)/2
60=(10t^2)/2
120=10t^2
12=t^2
so t = √12 = 3.46 sec
_____$___$$____$$___$__$$
here u=0m/s
v=?
g=10m/s^2
t=?
s=60m
s=ut+(at^2)/2
60=(0*t)+(10t^2)/2
60=(10t^2)/2
120=10t^2
12=t^2
so t = √12 = 3.46 sec
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