A ball is dropped from a balloon going up at a speed of 7 m/s. If the balloon was at a height 60 m at the time of dropping the ball, how long will the ball take in reaching the ground?
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Solution :
Initially ball is going upwards
Initial velocity=u= -7m/s
S=60m
a=g=10m/s2
From Second equation of motion
s=ut+1/2at²
60= - 7t +(1/2 )10 t²
60=-7t +5t²
5t² -7t -60=0
t=-7±√49-4x5(-60)/2x5
t=-7±√49+1200/10
t=-7±35.3/10
t=7+35.3/10 =4.2 sec [ as t cannot be negative]
∴ The ball will take 4.2 sec to reach the ground.
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