A ball is dropped from a balloon going up at a speed of 7m/s. If the balloon was at a height of 60m at the time of dropping the ball, how long will the ball take in reaching the ground?
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Answered by
1
✨Heya!!!!!✨
here is ur answer mate.......❤❤❤
Initial velocity (u)=0m/s
Final velocity (v)=7m/a
Distance or height(s)=60m
Time(t)=?
Acceleration (a)=?
To find acceleration:-
=>v^2=u^2+2as
=>7^2=0^2+2×a×60
=>49=0+120a
=>120a=49
=>a=49/120
=>a=0.40m/s^2
To find time:-
v=u+at
7=0+0.40×t
0.40t=7
t=7/0.49
t=17.5 seconds
ANSWER =17.5 SECONDS
HOPE IT HELPS U.....☺☺☺
✔✔✔✔✔✔✔✔
here is ur answer mate.......❤❤❤
Initial velocity (u)=0m/s
Final velocity (v)=7m/a
Distance or height(s)=60m
Time(t)=?
Acceleration (a)=?
To find acceleration:-
=>v^2=u^2+2as
=>7^2=0^2+2×a×60
=>49=0+120a
=>120a=49
=>a=49/120
=>a=0.40m/s^2
To find time:-
v=u+at
7=0+0.40×t
0.40t=7
t=7/0.49
t=17.5 seconds
ANSWER =17.5 SECONDS
HOPE IT HELPS U.....☺☺☺
✔✔✔✔✔✔✔✔
aggarwalreena290:
ohk
Answered by
1
Answer:
the answer of the question is 17.5s.
Explanation:
so we have;
Initial velocity (u)= 0m/s
final velocity (v). = 7m/s
Distance (s). = 60m
Acceleration (a) = ?
Time(t). = ?
so first we have to find acceleration;
v^2 = u^2 + 2as
7^2 =0°2 + 2 × a × 60
49 = 0 + 120a
49 = 120a
120a = 49
a = 49/120
a = 0.40m/s
Then we have to find time;
v = u + at
7 = 0 + 0.40 × t
7 = 0.40t
0.40t = 7
t = 7/0.40
t = 17.5s
I hope it help you. I think you understand.
If not tell me ok.
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