A ball is dropped from a balloon up to speed 10m/s if balloon was a height 40m at time of dropping the ball how long will the ball take time in reaching the ground
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Answered by
1
Answer:
Speed=7m/s
height=60m
So, initially, the ball is going the upward,
u=−7m/s,s=60m,a=g=10m/s
s=ut+21gt2
60=−7t+2110t2
5t2−7t−60=0
t=2×57±49+4×5×60
t=107±35.34
Taking +ve sign then we get,
t=107±35.34=4.2s
Thus, the ball will take time in reaching the ground is:
4.2s
Answered by
0
Given,
Speed=7m/s
height=60m
So, initially, the ball is going the upward,
u=−7m/s,s=60m,a=g=10m/s
2
s=ut+
2
1
gt
2
60=−7t+
2
1
10t
2
5t
2
−7t−60=0
t=
2×5
7±
49+4×5×60
t=
10
7±35.34
Taking +ve sign then we get,
t=
10
7±35.34
=4.2s
Thus, the ball will take time in reaching the ground is:
4.2s
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