A ball is dropped from a building. it took 10 secs to reach the ground. find the height of the building(g=9.8m/s)
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u,initial velocity
t,time
u=0
t=4 s
g=9.8m/ s^{2}
s(height)=?
s=ut+1/2at^{2}
=0*4^2+1/2*9.8*4^2
=0+1/2*9.8*4*4
=78.4m
t,time
u=0
t=4 s
g=9.8m/ s^{2}
s(height)=?
s=ut+1/2at^{2}
=0*4^2+1/2*9.8*4^2
=0+1/2*9.8*4*4
=78.4m
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