Question

A ball is dropped from a building of 10m, it reaches ground after 20seconds. Find the final velocity​

Answer 1

Answer:

Explanation:

Height/Distance = 10 m

Time = 20 s

Using Second equation of motion, we get -

s=ut + $\frac{1}{2}$at²

10 = 20u + $\frac{1}{2}$ (10)(10)²

20u = 10 - $\frac{1}{2}$ (10)³

u = -24.5     (- sign because it is in opposite direction)

thus the final velocity is 24.5 m/s

Hope this helps . . . also comment if further doubt