Question

a ball is dropped from a building of height h meters . Calculate the distance travelled by it in n seconds​

Answer 1

According to the Question,

Height = (h) m.

Time = (n)s

let the distance travelled be 'd'.

Then by second law,

S = ut + ½at²

= 0t + ½v/t × t² (where u=0,ball is dropped from a point)

= 0 + ½vt

= ½ vn units.

Answer 2

$s = ut + at {}^{2} \times \frac{1}{2}$

Now,t=n sec.

u=0(because it was at rest)

Now

s=an

$s = an {}^{2} \times \frac{1}{2}$