a ball is dropped from a certain height find the speed of the ball at end of 2 seconds
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For the last part of the journey,
s=ut+(1/2)gt 2
Here s=6.2 m; u=? t=0.2s g=10 m/s 2
Putting these values we get, u=30m/s
Now, for the upper portion, v 2 =u 2 +2gh, here, u=initialvel=0; v=30m/s,
Putting the values we get h=45 m.
So the total height = (45+6.2)m=51.2m
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