Question

a ball is dropped from a certain height it takes 2sec to cross the last 6m before hitting the ground find the height from which the ball is dropped take G=10m/s2​

Answer 1

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Answer 2

By Newton’s second equation of motion;

Distance (S) = ut +  

Here S = 6m; t = 0.2s; g = 10m/s2;

⇒ 6 = 0.2u +  

⇒ 6 = 0.2u +  

⇒ 6 = 0.2u + 0.2

⇒ 0.2u = 6 – 0.2

⇒ 0.2u = 5.8.

⇒ u = 29 m/s.

Hence final speed (v) of the ball after it traveled ‘X’ distance is 29m/s.