A ball is dropped from a certain height. It took the ball 10 seconds to reach the ground. Find the height at which the ball was dropped? assuming acceleration of dropped objects as 10 m/s^2
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3
s = ut + 1/2 at^2
= 0 + 1/2×10×100
= 500m
initial vel. is zero
!!??????
height is 500 m
third law of motion
Answered by
0
s= ut+1/2 at,^2
=0+1/2×15×100
=300m/sec^2
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