Question

. A ball is dropped from a height h. The velocity of the
ball when it reaches the ground is 10 ms-1. Find h.
(Take g = 10 ms-2).​

Answer 1

Answer:

5 m

Explanation:

given :

u = 0

v= 10m/s

h = ?

g= 10m/s²

v² = u² + 2gh. (for downward motion, sign convention is +ve)

therefore,

h = v²/2g

h = 100/20

h = 5 m