Question

A ball is dropped from a height if it takes 1 second to cross the last 55 meters before hitting the ground find height from which it was dropped

Answer 1

Answer:

176.4m

Explanation:

Ball is dropped

therefore , u =0

a = +g = 10

Using , Distance travelled in nth second = u + a/2 ( 2n - 1 )

55= 0 + 10/2 ( 2n-1 )

55 = 5 ( 2n - 1 )

2n - 1 = 55/5

2n - 1 = 11

2n = 12

n = 6 seconds

Using , s= u + 1/2at square

s = 0 + 1/2 × 9.8 ×6×6

s = 176.4m