Question

A ball is dropped from a height of 10 m.
It strikes the ground and rebounds up
to a height of 2.5 m. During the collision
the percent loss in the kinetic energy:
a) 50%
b)35%
c)40%
d)75%​

Answer 1

Answer:

hey mate,

your answer is 75%

Explanation:

According to law of conservation of energy,

initial KE = mgh

similarly, final KE = mgh'

change in KE = mg(h - h')

% of change in KE =[ mg(h -h')/mgh] × 100

=( 7.5/ 10) × 100

= 75%

hope this would help you!!