Question

a ball is dropped from a height of 100 m. it after rebounding from the ground it raises to a height of 80 m. then value of coefficient of restitution is ( take g = 10 m/ s ² )​

Answer 1

Answer:

10/80

1/8

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Answer 2

Given: Ball dropped from height 100m. After rebounding, raises to height 80m.

To find: Coefficient of restitution

Explanation: Let coefficient of restitution be e.

Velocity gained after falling from 100m

=$\sqrt{2gh}$

= $\sqrt{2 \times 10 \times 100}$

= $\sqrt{2000}$

Velocity required for going 80m

=$\sqrt{2gh}$

=$\sqrt{2 \times 10 \times 80}$

=$\sqrt{1600}$

Now, e= Velocity of separation / velocity of approach

=

= $\sqrt{ \frac{1600}{2000} }$

= $\sqrt{ \frac{4}{5} }$

Therefore, the coefficient of restitution is $\sqrt{ \frac{4}{5} }$