Question

A ball is dropped from a height of 100m. Another ball was thrown upwards from the bottom of the tower with a speed 50m/s. Where do they meet?

Answer 1

let distance travelled by ball thrown downward be x then distance travelled by ball thrown upward will be 100-x so using S=ut-1/2gt² - x= 0×t-10×t²/2 = -5t² x=5t² 100-x= 50×t-10×t²/2= 50t- 5t² from x=5t² 100-5t²= 50t-5t² t= 2sec. so. x= 5×2²=20m so distance travelled by ball thrown down =20m and ball thrown up travelled 80m and they take 2sec . to meet