A ball is dropped from a height of 10m.if the energy of the ball reduces by 40% after striking the ground, how much high can the ball bounce back? (g=10 ms-2
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v^2=u^2+2as
=2×10×10
=200
KE=1/2mv^2
60%=60m
mgh=1/2mv^2
mgh=60m
h=6m
=2×10×10
=200
KE=1/2mv^2
60%=60m
mgh=1/2mv^2
mgh=60m
h=6m
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